Canadian born wwe wrestler Bobby Roode net worth of $2 million. Find Bobby real name, height, age, wife, salary to family detail. His original name is Robert F. Roode. He is a Canadian professional wrestler who made his first debut in 1998 with the WWF and is presently working with the same after working on various pedestals. He was born in Scarborough, Ontario, Canada on January 1, 1977 (age 40), and his birth sign is Capricorn. He is North American by ethnicity and a Canadian by Nationality.
|Full Name||Robert Roode Jr|
|Birth Date||January 1, 1977|
|Height||6 feet / 1.83 m|
|Parents||Bob Roode and Sandy Roode|
|Net Worth||$2 Million|
|Source of Income||wrestler|
He started his career in 1998 with WWE, after a year of training under Sean Morley and Shane Sewell, in his hometown Peterborough, Ontario. His debut wrestling match as, “Total” Lee Awesome was against Pete Rock. His teaming with WWE was for almost 16 years from 1998-2004. He then had 12 years of reign, working for, the Total Nonstop Action Wrestling (TNA) from 2004 to 2016, where he won six-time “TNA World Tag Team” Champion title, becoming the longest veteran champion, breaking all records in the history of TNA. In 2016, he joined NXT and defeated Shinsuke Nakamura to win the NXT Championship, pushing its standard to another limit as promised. And finally, his biggest roster call-up was, joining the WWE’s SmackDown LIVE.
Although his name is not added under Richest Wrestler list however he is still earning well.Interestingly, he also acted in a few movies such as, “Against All Odds” (2011), “Final Resolution” (2009) and “Bound for Glory”(2009). He boasts 2 decades of experience and championship against all odds and is an irreplaceable hero, with or without his titles. He is married to Tracy Roode, and the couple is blessed with three sons, Robert III, Riley, and Nicholas.